C#简单实现的远程命令程序

来源： 作者： 出处：巧巧读书 2006-10-13 进入讨论组

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　　private void button1_Click(object sender, System.EventArgs e)

{

ConnectionOptions opt=new ConnectionOptions();

opt.Username=UserBox.Text;

opt.Password=PassBox.Text;

ManagementScope scope=new ManagementScope("\\\\"+IPbox.Text+"\\root\\cimv2",opt);

try

{

scope.Connect();

ObjectGetOptions o = new ObjectGetOptions();

ManagementPath path=new ManagementPath("Win32_Process");

ManagementClass processClass = new ManagementClass(scope,path,o);




ManagementBaseObject inParams = processClass.GetMethodParameters("Create");


inParams["CommandLine"] = CommandBox.Text;




ManagementBaseObject outParams = processClass.InvokeMethod ("Create", inParams, null);

}

catch(Exception ee)

{

MessageBox.Show(ee.Message,"Error");

}

}



private void button2_Click(object sender, System.EventArgs e)

{

Application.Exit();

}

} 更多内容请看Linux命令简介专题，或进入讨论组讨论。

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