Sql server数据库开发常用汇总

来源：作者：出处：巧巧读书 2007-10-09 进入讨论组

1.按姓氏笔划排序:
Select * From TableName Order By CustomerName Collate Chinese_PRC_Stroke_ci_as
2.资料库加密:
select encrypt('原始密码')
select pwdencrypt('原始密码')

select pwdcompare('原始密码','加密後密码') = 1--相同；否则不相同 encrypt('原始密码')
select pwdencrypt('原始密码')
select pwdcompare('原始密码','加密後密码') = 1--相同；否则不相同
3.取回表中栏位:
declare @list varchar(1000),@sql nvarchar(1000)
select @list=@list+','+b.name from sysobjects a,syscolumns b where a.id=b.id and a.name='表A'
set @sql='select '+right(@list,len(@list)-1)+' from 表A'
exec (@sql)
4.查看硬碟分区:
EXEC master..xp_fixeddrives
5.比较A,B表是否相等:
if (select checksum_agg(binary_checksum(*)) from A)
=
(select checksum_agg(binary_checksum(*)) from B)
print '相等'
else
print '不相等'
6.杀掉所有的事件探察器进程:
DECLARE hcforeach CURSOR GLOBAL FOR SELECT 'kill '+RTRIM(spid) FROM master.dbo.sysprocesses
WHERE program_name IN('SQL profiler',N'SQL 事件探查器')
EXEC sp_msforeach_worker '?'
7.记录搜索:
开头到N条记录
Select Top N * From 表
-------------------------------
N到M条记录(要有主索引ID)
Select Top M-N * From 表 Where ID in (Select Top M ID From 表) Order by ID Desc
----------------------------------
N到结尾记录
Select Top N * From 表 Order by ID Desc
8.如何修改资料库的名称:
sp_renamedb 'old_name', 'new_name'
9：获取当前资料库中的所有用户表
select Name from sysobjects where xtype='u' and status>=0
10：获取某一个表的所有栏位
select name from syscolumns where id=object_id('表名')
11：查看与某一个表相关的视图、存储过程、函数
select a.* from sysobjects a, syscomments b where a.id = b.id and b.text like '%表名%'
12：查看当前资料库中所有存储过程
select name as 存储过程名称 from sysobjects where xtype='P'
13：查询用户创建的所有资料库
select * from master..sysdatabases D where sid not in(select sid from master..syslogins where name='sa')
或者
select dbid, name AS DB_NAME from master..sysdatabases where sid ＜> 0x01
14：查询某一个表的栏位和资料类型
select column_name,data_type from information_schema.columns
where table_name = '表名'
[n].[标题]:
Select * From TableName Order By CustomerName
[n].[标题]:
Select * From TableName Order By CustomerName

原文地址﹕
http://www.msuniversity.edu.cn/bbs/dispbbs.asp?boardID=22&ID=392&page=1

专题:http://www.qqread.com/sqlserver/2007/10/f342042.html